1 kg of water at 100° C is converted into steam at 100° C by boiling at atmospheric pressure. The volume of water changes from 1.00 x10 -3 m 3 as a liquid to 1. 671 m 3 as steam. The change in internal energy of the system during the process will be (Given latent heat of vaporisation = 2257 kJ / kg, Atmospheric pressure = 1 x 10 5 Pa)
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The work to be done in the process is given by dW=PdV
=1 x 10 5 Pa x (1. 671 - 0. 001) m 3
=1.670x10 5 J
The change in heat energy during the vaporisation process can be calculated as follows-
=22.57x 10 5 J
Hence, the change in internal energy in the process is given by
= (22.57-1.67) x 10 5 J
=20.9 x 10 5 J
=2090 kJ
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